Help with mixing equation

[Slyder777]

OK, sorry for the noob post, but I am missing something here and need a pro to tell me what it is.

I am studying for my license exam and this is an exact question on the mixing part of the study guide.

You need to apply a pesticide premise spray for livestock pests to an area of 70,000 sq. ft. The pesticide is a 57% EC (5 lb/gal.) formulation. The label recommended rate is 1 ounce per 3,000 sq. ft. and requires an application of a 2 percent spray mixture in an oil carrier (oil weight = 7.05 lb/gal).

A. How many ounces of pesticide concentrate do you need to treat the premises?

B. How many gallons of oil carrier do you need to prepare the 2 percent mixture?

Question A is an obvious and easy answer. Question B is throwing me for a loop. I have the answer, and still can't get how they got to it. I have had no other problems with any of the mix eqautions to this point.

Also, the first two answers they provide in the book were wrong. They had to post a correction with two new answers. I am starting to wander is their answer for B is still wrong.

Again, I know the answer, but need to know how to get there. THanks for any help.

Shawn

[americanlawn]

Seems they are trying to throw you for a loop (trick question). Multiply the answer of question A times .02

That's my best guess.

[mkroher]

hi. it says the "label recommends a rate of 1oz per 1000sqft". I think that means solution, so the info about the 57% stuff is non important.

A). 1oz/3000sqft * 70,000sqft = 23.3oz sol

B) 23.3oz sol * 1 gal/sol / 128oz * 100gal oil / 2 gal sol = 9.10 gal oil ??

That's my guess.

[RigglePLC]

I will try. I agree, 23.3 ounces concentrate needed.

For part B. 23.3 ounces will be 2 percent of your new oil solution.

Divide 23.3 by .02

Result 116.5 ounces. The total amount to be applied.

Divide by 128. You get .91 gallon of oil carrier required.

[Leaf Jockey]

My turn.
1 ounce concentrate added to 49 ounces of carrier is a 2% solution.
49 times 23.3 = 1141.7 ounces
divide by 128 = 8.91

Scott

[Slyder777]

WEll, at least I know I'm not the only one who had trouble with this problem. I am really wondering if the question is worded wrong. Leaf Jocky is the closest so far. I will wait for a few more replies and then post what the book says is the correct answer for B. 23.3 oz is correct for A.

I have disected this thing from front to back, inside and out and can't seem to figure out how they got the answer they did. Of course the reason that worries me is I do not want to run into a problem like this in the course of a day and not know how to resolve it.

Thanks again for the replies. Let's hope someone on here can figure this thing out.

What is really frustrating is most other equations and problems were explained and talked about. Nothing in all the study material talks about a problem like this.

[RigglePLC]

Whoops! My mistake.

23.3 divided by .02 is 1165 ounces

Divide by 128 to get 9.1 gallons.

[Leaf Jockey]

I think you need to subtract the 23.3 ounces from the 1165 so your answer reflects just the amount of carrier. Thats how I figure it anyway.

Scott

[Slyder777]

OK, finally figured it out.

Here is the equation given to use for EC mixing using percentages.

gals of EC needed = (gals of spray wanted) x (% of ai wanted) x (lbs/gal of carrier) divided by lbs ai per gallon x 100

So here is what the equation should look like using the information we already know.

.18 = X(Gals of spray wanted) x 2 x 7.05 divided by 5 x 100

.18 = 14.10x divided by 500

.18 = .0282X

You then use basic algebra and divide .18 by .0282 to find X which is 6.38. 6.38 is the answer given in the book.

So you need 6.38 gallons of oil to carry the 23.3 ounces of ai to treat the 70,000 sqaure feet. Whew.

Knew it was there somewhere, but dang, didn't think it would be that hard.

BTW .18 was achieved by dividing the total ounces 23.3 Ounces by 128 to determine the number of gallons of ai needed.

Thanks for the help guys. Now we know how to get from poiont A to Point B via Point R O X D U V C. :dizzy: Have a good night.

Shawn

[RigglePLC]

Mkrohr is right. Ok, but problem didn't mention they wanted 2 percent by weight.

Convert 23 ounces to pounds by dividing by 128, getting .1796

Multiply by 5 to get the weight of pesticide, .8984 lbs

Divide by the percent .02 to get pounds of oil, 44.9

Divide by 7.02 to get gallons of oil, 6.399

[jayman93941]

I could not understand the question as written with the answers provided so I called the A&M office that distributes the study material (Dr. Mary Ketchen 979 845-1099. She said that they were aware of this question (chapter #16, question #17).


She also said the question started out has a way to show that (in this example) to make a finished spray (like the example on page 165 for ants) but this requires a 2 percent finished spray mixture with an oil carrier (7.05 lb/gal.) using a pesticide of 57% EC (5 lb./gal): How many parts (ounces) of pesticide is needed (to treat the total area) and added to how many parts (gallons) of the oil carrier for a 2 % mixture?

The book answer is incorrect.

Her hint she gave me over the phone: If a pesticide is formulated as a 57 percent emulsifiable concentrate then to make a one percent finished spray, I would need to add one part pesticide to 56 parts of carrier.

She was very nice and sent me a better list of study questions with an answer key and examples of how they could be done.

I noticed other states do not question #17:

http://pmep.cce.cornell.edu/facts-slides-self/core-tutorial/module17/index.html

[Ric]

YO

I taught Materials calculation at a state college here in Florida.

The Basic Point you all are missing is the calibration of your spray unit. Any mixing of chemicals should start will how many gallons you plan to apply per thousand Sq Feet. Multiply the gallons per sq ft times the total sq feet to get your total gallons of mixed material.

If you use the 100 gallon example given then you must apply at the rate of 1.43 gallons per thousand in order to get the correct application of material.

[Ric]

OK, sorry for the noob post, but I am missing something here and need a pro to tell me what it is.

I am studying for my license exam and this is an exact question on the mixing part of the study guide.

You need to apply a pesticide premise spray for livestock pests to an area of 70,000 sq. ft. The pesticide is a 57% EC (5 lb/gal.) formulation. The label recommended rate is 1 ounce per 3,000 sq. ft. and requires an application of a 2 percent spray mixture in an oil carrier (oil weight = 7.05 lb/gal).

A. How many ounces of pesticide concentrate do you need to treat the premises?

B. How many gallons of oil carrier do you need to prepare the 2 percent mixture?
Question A is an obvious and easy answer. Question B is throwing me for a loop. I have the answer, and still can't get how they got to it. I have had no other problems with any of the mix eqautions to this point.

Also, the first two answers they provide in the book were wrong. They had to post a correction with two new answers. I am starting to wander is their answer for B is still wrong.

Again, I know the answer, but need to know how to get there. THanks for any help.

Shawn

Seems they are trying to throw you for a loop (trick question). Multiply the answer of question A times .02

That's my best guess.

Pasture Grass

Go straight to 5th grade, Do Not pass go do not collect $ 200.00

hi. it says the "label recommends a rate of 1oz per 1000sqft". I think that means solution, so the info about the 57% stuff is non important.

A). 1oz/3000sqft * 70,000sqft = 23.3oz sol

B) 23.3oz sol * 1 gal/sol / 128oz * 100gal oil / 2 gal sol = 9.10 gal oil ??

That's my guess.

mkroher

9.1 gal of oil in 100 gal of water is a 9.1% oil solution

I will try. I agree, 23.3 ounces concentrate needed.

For part B. 23.3 ounces will be 2 percent of your new oil solution.

Divide 23.3 by .02

Result 116.5 ounces. The total amount to be applied.

Divide by 128. You get .91 gallon of oil carrier required.

Riggle

Try again

My turn.
1 ounce concentrate added to 49 ounces of carrier is a 2% solution.
49 times 23.3 = 1141.7 ounces
divide by 128 = 8.91

Scott

Totally out of the Box


Whoops! My mistake.

23.3 divided by .02 is 1165 ounces

Divide by 128 to get 9.1 gallons.

OPPS Try again

I think you need to subtract the 23.3 ounces from the 1165 so your answer reflects just the amount of carrier. Thats how I figure it anyway.

Scott

Better figure again

OK, finally figured it out.

Here is the equation given to use for EC mixing using percentages.

gals of EC needed = (gals of spray wanted) x (% of ai wanted) x (lbs/gal of carrier) divided by lbs ai per gallon x 100

So here is what the equation should look like using the information we already know.

.18 = X(Gals of spray wanted) x 2 x 7.05 divided by 5 x 100

.18 = 14.10x divided by 500

.18 = .0282X

You then use basic algebra and divide .18 by .0282 to find X which is 6.38. 6.38 is the answer given in the book.

So you need 6.38 gallons of oil to carry the 23.3 ounces of ai to treat the 70,000 sqaure feet. Whew.

Knew it was there somewhere, but dang, didn't think it would be that hard.

BTW .18 was achieved by dividing the total ounces 23.3 Ounces by 128 to determine the number of gallons of ai needed.

Thanks for the help guys. Now we know how to get from poiont A to Point B via Point R O X D U V C. :dizzy: Have a good night.

Shawn

Shawn

I am glad you don't treat my lawn

Mkrohr is right. Ok, but problem didn't mention they wanted 2 percent by weight.

Convert 23 ounces to pounds by dividing by 128, getting .1796

Multiply by 5 to get the weight of pesticide, .8984 lbs

Divide by the percent .02 to get pounds of oil, 44.9

Divide by 7.02 to get gallons of oil, 6.399

Riggle

Never any question about weight. You are trying to make a simple thing hard.



OK the answer is very simple

You have 70K that has to be treated. Your spray rig normally applies at 1 gallon per k. Part B asks for Part A to be applied in a 2% oil solution. You need 70 Gallons of finish spray to apply. 2% of 70 gallons is 1.4 gallons or 1 gal 51oz of oil.

If you calibrate at 2 gallon a thousand, 140 gallon of finish spray is needed with 2.8 gallons (230 oz) of oil to make a 2% solution of oil.

[Leaf Jockey]

OK the answer is very simple

You have 70K that has to be treated. Your spray rig normally applies at 1 gallon per k. Part B asks for Part A to be applied in a 2% oil solution. You need 70 Gallons of finish spray to apply. 2% of 70 gallons is 1.4 gallons or 1 gal 51oz of oil.

If you calibrate at 2 gallon a thousand, 140 gallon of finish spray is needed with 2.8 gallons (230 oz) of oil to make a 2% solution of oil.[/QUOTE]


I think you have proven that we all can make mistakes. Including you.

Scott

[Ric]

I think you have proven that we all can make mistakes. Including you.

Scott

Leaf Jockey

I certainly am not perfect. However it is a sad day when so many CERTIFIFED PESTICIDE OPERATORS who apply chemicals on a daily bases can't figure out a simple mixing instruction. Then they show their Ignorance on the world wide web. Mark one up for the TREE HUGGERS. People complain that Florida has the Hardest Pesticide test in the Nation and heavy requirement to even sit for it. But I am Darn Glad Florida doesn't give away Pesticide Certification like the rest of the nation. We lose good chemical tools every day Not because they are bad. But because they are misused by people like your self who don't have 8th grade math skills.

BTW I started out Laughing at this thread and ended up crying at the lack of intelligence. They say Lawn care needs a strong back and weak mind, But I didn't realize how weak the minds were until this thread.

[Victor]

Leaf Jockey

I certainly am not perfect. However it is a sad day when so many CERTIFIFED PESTICIDE OPERATORS who apply chemicals on a daily bases can't figure out a simple mixing instruction. Then they show their Ignorance on the world wide web. Mark one up for the TREE HUGGERS. People complain that Florida has the Hardest Pesticide test in the Nation and heavy requirement to even sit for it. But I am Darn Glad Florida doesn't give away Pesticide Certification like the rest of the nation. We lose good chemical tools every day Not because they are bad. But because they are misused by people like your self who don't have 8th grade math skills.

BTW I started out Laughing at this thread and ended up crying at the lack of intelligence. They say Lawn care needs a strong back and weak mind, But I didn't realize how weak the minds were until this thread.

Umm... If I were you Ric, I definitely wouldn't make any references to someone having a lack of an education. It's a safe bet to say you write on a 6th grade level or less. For your information, the correct way to spell the word bases, in the context you used it in, would be basis.

While you're knowledgeable when it comes to treating lawns and pest control, you've demonstrated more times than I care to recall that you're not intelligent enough to have any business critiquing any other member's intelligence.

Take it easy, stop being such a miscreant and get off your darn soap box!

[Ric]

Umm... you write on a 6th grade level or less.

Victor

Thank You

I consider the 6th grade writing skills a complement since English is not my 1st language.

[Slyder777]

Hey Ric, thanks for the interesting post, I think. However, maybe you didn't notice, I am a noob and fully admitted that prior to the post.

As well, the answer I provided IS the corrected answer provided in the book. So not only could nonone on here get the correct answer, the freaking people that wrote the dang thing couldn't get the correct answer.

So who did get the correct answer, oh yea, that was ME. Why, not because I am a pro, but because I will not just take a guess and go on. That is what will make me a great applicator. Problems will come up. And when they do I will n ot just pass them by or ignore them as many applicators do. I will address them and research them and maybe even bring them to a site like this in hopes of getting honest, helpful, non-smart ass answers.

At any rate, the test was passed, with a 96 I might ad. The license is in place and equipment on the way. I sincerely hope I will be able to come here with questions that will arise without being worried about being ostracized for being a noob.

Not trying to attack you, maybe I read more into your post. Just thought it was a little over the top.

BTW, the equation I gave in my post in which I provided the correct answer is the exact way it was ment to be answered, at least according to the TDA people I talked to. I can only refer to what I was taught.

Thanks again. Look forward to future help here.

[Victor]

And welcome to Lawnsite! I'm sure I'm not alone when I tell you that I hope you stick around.

[LawnTamer]

Yes, welcome Slyder.

It is interesting that many of us who have done this for many years would have trouble with this. May I point out what I believe to be the causes.

1. Many of us probably don't need to figure mix ratios using AI on a regular basis. The last time I had to was several years ago. I was using an off brand pre-emergent that used AI in it's application without providing chart. Every other time I've had to mix using AI or even an X% solution, the labeling provides a simple chart, which shows amount of carrier, product and solution for whatever X% is.

2. If most of you are like me, you have maybe a dozen or so pesticides which you regularly use. I have used most of them for years, I know exactly what rate I achieve the best results at. For example, I use one product that lists the use rates by weight, instead of volume, (what a PITA, makes me want to write a dirty letter to the co.) anyway, I measured it all out the first year I used it. I made my own chart showing that .18lbs AI = 68 oz by volume in my measuring cup etc, etc. When I occasionally add a new chemical to my arsenal, or test one out on a problem, the labeling instructions are rarely that difficult.

I bet most of us have our little arsenal, and are very competent in using it.

[Ric]

Slyder

May I suggest you print this thread and take it to your Agi Inspector. Ask him which answer is correct. Your answer failed to give the total amount of finish spray or the volume of material applied per square footage. Hello, I believe you must know how much finish spray to apply in order to make a correct application.

Yes I jumped on your thread because of the total lack of understanding of the chemical application process. Let me quickly explain the proper way to approach a chemical application.

1st Identify the problem as a either a cultural of chemical problem.

2nd Determine if that problem is to the point where intervention is needed.

3rd Understand or research the Life Cycle of that insect to determine what intervention is needed that has the least impact on the environment. This includes understanding. If a Chemical has a Insect listed on the label, That doesn't mean that chemical is the best one to use on that insect. An Example might be Liquid Sevin the broadest labelled pesticide on the market. While Sevin is great on chewing insects (Caterpillars Particularly), It is not very effective against Ants which are also on the label. Liquid Sevin also impacts earth worms so it is not the best choice to use for controlling ants.

4th Read the label of the product for correct application and understand the life cycle of your pest to determine your best approach. If you problem is weeds that are on the surface, a lower volume of finish spray is needed to reach your target. If you are after subterranean pests you must use a larger volume of finish spray to reach them.

5th Do the math of how many gallons of Finish spray are needed and proper amounts of Pesticide to mix.

6th Check your equipment for leaks and proper calibration, changing tips and pressure setting to do the job correctly.

7th Check with your customer for a time the application can be made as to not conflict with their schedule. Make sure they understand to keep Pets and Children off the area for the required re-entry time.

8th Wearing your PPE as per label, Mix and apply the chemicals. Post warning signs on the property and record the application in your log book. Give your customer a written statement of what and when a chemical was applied.

Finally, Use what little common sense god gave you to think the whole process out.

[LawnTamer]

Slyder

May I suggest you print this thread and take it to your Agi Inspector. Ask him which answer is correct. Your answer failed to give the total amount of finish spray or the volume of material applied per square footage. Hello, I believe you must know how much finish spray to apply in order to make a correct application.

Yes I jumped on your thread because of the total lack of understanding of the chemical application process. Let me quickly explain the proper way to approach a chemical application.

1st Identify the problem as a either a cultural of chemical problem.

2nd Determine if that problem is to the point where intervention is needed.

3rd Understand or research the Life Cycle of that insect to determine what intervention is needed that has the least impact on the environment. This includes understanding. If a Chemical has a Insect listed on the label, That doesn't mean that chemical is the best one to use on that insect. An Example might be Liquid Sevin the broadest labelled pesticide on the market. While Sevin is great on chewing insects (Caterpillars Particularly), It is not very effective against Ants which are also on the label. Liquid Sevin also impacts earth worms so it is not the best choice to use for controlling ants.

4th Read the label of the product for correct application and understand the life cycle of your pest to determine your best approach. If you problem is weeds that are on the surface, a lower volume of finish spray is needed to reach your target. If you are after subterranean pests you must use a larger volume of finish spray to reach them.

5th Do the math of how many gallons of Finish spray are needed and proper amounts of Pesticide to mix.

6th Check your equipment for leaks and proper calibration, changing tips and pressure setting to do the job correctly.

7th Check with your customer for a time the application can be made as to not conflict with their schedule. Make sure they understand to keep Pets and Children off the area for the required re-entry time.

8th Wearing your PPE as per label, Mix and apply the chemicals. Post warning signs on the property and record the application in your log book. Give your customer a written statement of what and when a chemical was applied.

Finally, Use what little common sense god gave you to think the whole process out.

While everything you said is correct Ric, one needs to have a realistic approach to pest control, whether it be outdoor or indoor. IPM (integrated pest management) is important, but there is only so much you can do when it is not your property. Following all the steps you outlined for each application would take too long to do the volume required to be profitable. Unless you are doing big, high profit jobs.
In my real world experience having done both indoor and out door pest control, one has to balance customer education, IPM and the need to satisfy the client. In many cases adequate pest control could be achieved through sanitation and proper cultural practices, however, the truth is that many clients are slobs, people don't water properly, and some people want pest control not because they have an actual infestation, but because they have some type of bug phobia.
Is it ideal or even reasonable that many clients simply don't ever want to see a spider in/on their home ever? Of course not, but it's what they want, and if you won't give it to them, someone else will.

[Ric]

Lawntamer

Experience should allows us to make these important decision very quickly. But no matter if you are Playing Golf, Baseball or Bowling the Fundamentals of how you swing the Club, Bat or Ball make for your success. Fail to follow the fundamentals and even Tiger Wood will slice a ball out of bounds. You are correct in the fact you must Play your Lie. Not all pest control jobs are played on a smooth green. When in the ruff you must pull out your sand wedge and just fire away. But at the same time you should swing that Sand Wedge with the same type of fundamentals that you use on your # 1 Driver. Remember even Tiger Wood still goes to a Golf Pro to keep his game sharp and we go to CEU classes for the same reason. Forgetting Basics is the sure sign of failure to come. Failure to read and understand Mixing instruction is failure before you start.

[rcreech]

Lawntamer

Experience should allows us to make these important decision very quickly. But no matter if you are Playing Golf, Baseball or Bowling the Fundamentals of how you swing the Club, Bat or Ball make for your success. Fail to follow the fundamentals and even Tiger Wood will slice a ball out of bounds. You are correct in the fact you must Play your Lie. Not all pest control jobs are played on a smooth green. When in the ruff you must pull out your sand wedge and just fire away. But at the same time you should swing that Sand Wedge with the same type of fundamentals that you use on your # 1 Driver. Remember even Tiger Wood still goes to a Golf Pro to keep his game sharp and we go to CEU classes for the same reason. Forgetting Basics is the sure sign of failure to come. Failure to read and understand Mixing instruction is failure before you start.


Ric,

Even though you usually come across wrong, talk down to most and don't have much respect for anyone...you almost always make sense and are right!

I know you don't care...:) but if you had a little more cooth, I think people would listen to you. You are very intelligent and know you stuff, but when people read your attitude they just get po'd and I think it discredits your facts.

JMO...

I get caught up in this sometimes also, so technically the pot is calling the kettle black, as it is easy to get short on here when it comes to opinions.

[Ric]

Ric,

Even though you usually come across wrong, talk down to most and don't have much respect for anyone...you almost always make sense and are right!

I know you don't care...:) but if you had a little more cooth, I think people would listen to you. You are very intelligent and know you stuff, but when people read your attitude they just get po'd and I think it discredits your facts.

JMO...

I get caught up in this sometimes also, so technically the pot is calling the kettle black, as it is easy to get short on here when it comes to opinions.

rcreech

It does no good to drop to your level. The goal is to bring you up to my level. BTW I have only been a Certified Operator for 5 years now and in the pesticide business for a total of 7 years. I read misinformation posted by people who claim to be in business for 30 or more years.

[rcreech]

rcreech

It does no good to drop to your level. The goal is to bring you up to my level. BTW I have only been a Certified Operator for 5 years now and in the pesticide business for a total of 7 years. I read misinformation posted by people who claim to be in business for 30 or more years.


Thank you for proving my point! Just the facts Ric....just the facts!

I didn't mean my post in a bad way! What I am saying is you have a lot to offer but I don't think people listen to you or take you serious because of the way you come across. I know how you are so I look through it!

So drop to my level? Afraid to ask....but what level do you think I am on? What do you mean by that anyway?

[Slyder777]

[QUOTE=Ric;2067041]Slyder

May I suggest you print this thread and take it to your Agi Inspector. Ask him which answer is correct. Your answer failed to give the total amount of finish spray or the volume of material applied per square footage. Hello, I believe you must know how much finish spray to apply in order to make a correct application.

Ric,

May I suggest you open your eyes and read the question as it was posed to me. The question was how many gallons of oil carrier were needed for the 2% solution. Period. It did not ask for the total mix volume. The answer I gave is the answer, the corrected answer, provided by the TEXAS DEPARTMENT of AG. If you want to march your holier than thou, arragant little tail down to Austin and take the issue up with them, fine, but don't put me through the ringer for trying to learn the business from pro's here on this site. My facts are right. Matter of fact, I try to always make sure my facts are right or I don't post on a forum like this.

So, if it makes you feel important to belittle me, than no problem. I try to live my life like my savior and he went through much worse, surely I can endure you while here on this forum.

Shawn

[Ric]

Ric,

May I suggest you open your eyes and read the question as it was posed to me. The question was how many gallons of oil carrier were needed for the 2% solution. Period. It did not ask for the total mix volume. The answer I gave is the answer, the corrected answer, provided by the TEXAS DEPARTMENT of AG. If you want to march your holier than thou, arragant little tail down to Austin and take the issue up with them, fine, but don't put me through the ringer for trying to learn the business from pro's here on this site. My facts are right. Matter of fact, I try to always make sure my facts are right or I don't post on a forum like this.

So, if it makes you feel important to belittle me, than no problem. I try to live my life like my savior and he went through much worse, surely I can endure you while here on this forum.

Shawn


Slyder

In post number 9 you stated you had the correct answer of 6.38 gallons of oil carrier and 23.3Oz of the pesticide. You also used a 100 gallons of water.

To quote you "Using basic algebra" let us work this formula backward using your answer to find the Total mixture volume and the Application rate per thousand sq feet. This is the real information needed to make a correct application regardless of what the question ask for. This is in fact the type of trick question on many tests to find out if the student understands the real problem. Which is very apparent no one answering this thread understood

.02 multiplied by the total volume, Equals 6.38 gallons of oil

Or .02 X The unknown = 6.38 gallons

.02/.02 X the unknown = 6.38/.02

1 X The unknown = 6.38/.02 = 319 total volume to treat 70,000 sq feet

319 gallons Total mix / 70,K sq feet = 4.55714 gallons of Finish spray per thousand sq ft.

Again 319 gallons of total mix X .02 = 6.38 gallons of oil.

THAT IS MATH AND IT IS AN EXACT SCIENCE. YOU CAN NOT ARGUE WITH IT AND YOU DID NOT HAVE THE CORRECT ANSWER. BTW I would be happy to discuss this answer with the Texas Dept of Agriculture any day.


I am sorry you kids are enumerate and get you nose bent out of shape when someone corrects you. I do not get upset when my English grammar is corrected. I believe the people on Lawnsite who have corrected my grammar have help me to learn better English.

[Victor]

What you need to realize, is that there's a big difference between correcting someone and belittling someone when they make a mistake like you often do.

[Ric]

What you need to realize, is that there's a big difference between correcting someone and belittling someone when they make a mistake like you often do.

Victor

Grow up and don't be so thin skinned, I am not your mother. You might not of given a incorrect answer. But those that did give incorrect answers and still don't understand the correct answer or reason for it. Should hang their head in shame to be called Certified Operator. This question has to do with everyday mixing problems. If you add surfactants of any kind to your tank mix, they are calculated by Percentage of solution. Not all label give charts for mixing by tank volume.

[Victor]

Victor

Grow up and don't be so thin skinned, I am not your mother. You might not of given a incorrect answer. But those that did give incorrect answers and still don't understand the correct answer or reason for it. Should hang their head in shame to be called Certified Operator. This question has to do with everyday mixing problems. If you add surfactants of any kind to your tank mix, they are calculated by Percentage of solution. Not all label give charts for mixing by tank volume.

This has nothing to do with me being thin skinned Ric. I don't take you seriously and never have. I know better. I'm just trying to keep you from running people off who might be thin-skinned. If I were new to this forum and saw how you responded to some of these posts, I'm not too sure I'd stick around. By the way, I think it's pretty funny that you of all people would have the nerve to tell someone to grow up. If that isn't the pot calling the kettle black, I don't know what is. :)

[txgrassguy]

What category is this, 1 C or F?
It sure as heck shouldn't be category 3A or 8.
I have found so many problems with the states' tests it isn't even funny anymore.
The question makes way too many assumptions to be valid so in effect it turns out to be just a basic math quiz.