AI in product?

Discussion in 'Pesticide & Herbicide Application' started by cycloneturf, Jul 26, 2008.

  1. cycloneturf

    cycloneturf LawnSite Member
    from midwest
    Posts: 6

    :usflag:How do you figure the total AI in pounds on a fifty pound bag?
    Example: 24-5-11 with Mach 2 1.33%

    **** 1.33 % / 50lbs = .026 lbs ?????? ***** This does not sound right

    Thanx for the help!
    :usflag:
     
  2. ICT Bill

    ICT Bill LawnSite Platinum Member
    Posts: 4,115

    If the number was 1% and you had 50 of anything it would be 0.50, yours would be somewhere around 0.65
     
  3. eagle1243

    eagle1243 LawnSite Member
    Posts: 3

    Multiply the % AI times total weight of product. Then divide by 100.

    1.33 % x 50 lbs = 66.5 lbs / 100 = .665 lbs
     
  4. JDUtah

    JDUtah LawnSite Silver Member
    from UT
    Posts: 2,636

    :clapping:
     
  5. RigglePLC

    RigglePLC LawnSite Fanatic
    Posts: 11,785

    Buy two bags. You have a hundred pounds. 1.33 percent then equals 1.33 pounds.
     
  6. cycloneturf

    cycloneturf LawnSite Member
    from midwest
    Posts: 6

    So with that said... a 19-0-6 Dimension .1 % would have .05 lbs of AI per 50 lb bag of fertilizer. :confused:
     
  7. Runner

    Runner LawnSite Fanatic
    Posts: 13,496

    That is correct. Seems strange, doesn't it? That is like Crosscheck (bifenthrin)...It is like 3 lbs. that does an acre, I believe.
     

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