# Check my Urea math please

Discussion in 'Fertilizer Application' started by TYTILIDIE, May 12, 2013.

1. ### TYTILIDIELawnSite Memberfrom Colorado SpringsPosts: 78

Correct me if I am wrong here please. I want to put down 1lb of dry flowable Urea per 1,000sq ft. My tank is putting out 2 gallons of mix per 1,000 sq ft. I have 50lb bags, I am spraying out of a 200 gallon tank so I am coming up with 100lbs of Urea in the tank. Sound right?

2. ### PamlicoLawnCareLawnSite Memberfrom Oriental, NCPosts: 80

Do you want to apply 1 lb. of urea per 1000 sq. ft. or 1 lb. of Nitrogen (N) per 1000 sq. ft.?...there's a big difference.

Need to know the % N of your 50 lb. bags of urea.

Also need to know total square footage of area to be applied.

I'm ASSUMING that you mean 1 lb. of N per 1000 sq. ft.

I'm also ASSUMING that your 50 lb. bags of urea contain 46% N.

If this is the case, one 50 lb. bag of 46% N urea contains 23 lbs. of N.

(50 lbs. X .46 = 23 lbs.)

If you want to apply 1 lb. of N per 1000 sq. ft., then one 50 lb. bag of urea will cover 23,000 sq. ft. or two bags of urea will cover 46,000 sq. ft., etc...

If you spray at a volume of 2 gallons per 1000 sq. ft. then one 50 lb. bag of urea in 46 gallons will give you 1 lb. of N per 1000 sq. ft. and you can spray 23,000 sq. ft.

With a 200 gallon tank, use four X 50 lb. bags of urea in 184 gallons to give a rate of 1 lb. of N per 1000 sq. ft. to cover 92,000 sq. ft.

Again, this ASSUMES that you mean 1 lb. of N per 1000 sq. ft. and that your 50 lb. bags of urea contain 46% N.

Let us know if this is not the case.

3. ### RicLawnSite Fanaticfrom S W FloridaPosts: 11,956

.

Or 4 1/3 bags of Urea in a 200 tank.

.

4. ### TYTILIDIELawnSite Memberfrom Colorado SpringsPosts: 78

This is all correct. I went and finally got the info off the bag. This kind of sucks because on my last round I only put two bags in. Oh well, learning experience right? Thanks for the help!

5. ### countryclublawnllcLawnSite Memberfrom MichiganPosts: 151

A pretty easy way to figure application rate of product for fertilizer is just put desired rate of the nutrient and divide by the percentage of that nutrient in the fert. If the desired rate is 1 lb. of N per thousand sq. ft. then it would go:

1/.46= 2.17

So 2.17 lbs of a 46-0-0 would be added per thousand sq. ft. of spray coverage which obviously depends on how many gallons of water go out /1000.

John