Estimate on Topsoil? Help?

Discussion in 'Landscape Architecture and Design' started by bender, Nov 19, 2003.

  1. bender

    bender LawnSite Member
    Posts: 16

    I'm in the process of estimating a topsoil Install. We have 20,000 sq ft. of area. The existing site is preped and graded. We just have to install 3-4" of Topsoil to surface. Can anybody please guide me in the correct direction, I never did an estimate this large.

    Thank you

  2. bobbygedd

    bobbygedd LawnSite Fanatic
    from NJ
    Posts: 10,178

    300-400 yds of topsoil.
  3. Team Gopher

    Team Gopher LawnSite Platinum Member
    from -
    Posts: 4,041

  4. Little Guy

    Little Guy LawnSite Member
    Posts: 118

    length x width x depth divided by 27 = yards needed
  5. bobbygedd

    bobbygedd LawnSite Fanatic
    from NJ
    Posts: 10,178

    what? how did u arrive at that? lets say u need to do a 10 x 10 area, 2 inches deep. i know u need i yd to do this. using your formula, u would go 10x10 x 2 divided by 27 =more than 7 yds? tell me how this formula works
  6. mpflood

    mpflood LawnSite Member
    Posts: 91

    I go by this
    2" deep, 1 yd covers 162 sq. ft
    3" deep, 1 yd covers 108 sq ft.
    4 " deep, 1 yd covers 81 sq ft.

    basic formula is 36 divided by # of inches = ?
    ? X9
    Dumont NJ:cool:
  7. NCSULandscaper

    NCSULandscaper Banned
    Posts: 1,557

    Thats because you are multiplying it by 2 ft instead of 2 inches

    10ftx10ftx.1666ft/27=.617yrds topsoil
  8. T.E.

    T.E. LawnSite Senior Member
    Posts: 799

    The formula that little guy uses is correct, and the one that I use.

    My math is pretty close to bobby's
  9. bobbygedd

    bobbygedd LawnSite Fanatic
    from NJ
    Posts: 10,178

    ncsu, now i see, thanks. but i still think a 10x10 area(100 sq ft) requires one yd at 2 inches deep. i do all my topsoil like this, it works out perfect.
  10. bligh61

    bligh61 LawnSite Member
    Posts: 239

    simply divide sq ft by 162 for a 2" cover, divide by 81 for a 4" cover and so on and so on; 20000 sq ft divided by 81 equals 246 yards

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