# First Gravel Drive Way. Help.

Discussion in 'Hardscaping' started by Cat_246B, Jul 29, 2012.

1. ### alldayrjLawnSite Gold Memberfrom Long island, NYPosts: 3,770

Do you have a dump truck or somewhere on the property to toss the old stone with the cat?
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2. ### Cat_246BLawnSite Memberfrom Beaver, UTPosts: 50

alldayjr: Theyhave a spot in their back yard where they want the old gravel, if they decide they don't want it, the Greenhouses down the road said they would take it.

3. ### jdo150LawnSite Memberfrom Hamden CtPosts: 74

Make sure you give the driveway pitch so the water can run off and compaction is key rent a large plate compactor or a vibratory roller. The soft spot can be taken care of by removing the soft soil (most Likely clay ) and then replacing with structural fill I.e. 3/4" process and compacting. And to figure out the amount of material you need the formula is length* width* depth (in feet )/27 to get cubic yards and remember that because your compacting the material you need to get more I usually use a 10% or 15% compaction factor.
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4. ### Cat_246BLawnSite Memberfrom Beaver, UTPosts: 50

jdo150: thanks for all of the information, I will remeber to compact it. (which I never though about.) Thanks for the formula too.

5. ### AztlanLCLawnSite Bronze Memberfrom Highland, NYPosts: 1,045

The problem with the previous formula is we usually install inches not feet of material this is my formula accounts for compaction

Lengh x width = area x (inches) / 240

6. ### jdo150LawnSite Memberfrom Hamden CtPosts: 74

Convert inches to feet # of (inches/12) example 4" /12=.33 feet
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7. ### jdo150LawnSite Memberfrom Hamden CtPosts: 74

Also how much of a factor is that formula it is way off aztlanlc. The problem is each soil compacts more or less and you need to figure that out your formula may work for common fill but not for a process or crusher run (whatever it's called in your area). There is too much of a factor. Also to the op if they sell in tons ask for the weight of the material it's probably close to 3000lbs a cubic yard.
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8. ### AztlanLCLawnSite Bronze Memberfrom Highland, NYPosts: 1,045

Not to start a discussion but lets say we have 500sqf. Area we need to fill in with 5" aggregate (my formula is for aggregate not soils) so if I use your formula this is all the math I have to do
5 / 12 = 0.416666. Then 500 x 0.416666 = 208 / 7.71 x 1.15 = 8.87 cys or 13.305 tons

I can assure you you will run short

My way. 500 x 5= 2500 / 240 = 10.41 cyd or 15.62

I'm confident and know from experience this will be exactly what I need, I have done like this for the past 8 years.

9. ### jdo150LawnSite Memberfrom Hamden CtPosts: 74

Where did you come up with the 240 just curious. I was tought my way at college and it hasn't failed me yet
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