I have recently removed the flatbed off of my Chev 1 ton dually and am in the process of adding a hydraulic cylinder to turn it into a flatbed dump. I was given a hydraulic cylinder that is 43" long, that fully extends to 73". It has a 4" bore and a 2" rod. It calculates to a bit over 28,000lbs of force. More then enough for the load I wil carry on this truck. I have a new pump etc. With such a long cylinder I have limited options as to how I can mount it. This system will be a "push" type similiar to the type used on dump trailers. Currently I have it mocked into position. How can I calculate the force generated by the mounting geometry I am hoping to use? Fixed end of the cylinder is 10" below the end attached to the bed, which makes the cylinder point up to start pushing up at a 13.5 degree angle. Attachement point on the bed is 30" from the pivot point the bed will pivot on. Bed is 108" long. I have tried to describe this as best I can. After looking at alot of 1 ton dumps I have tried to mimic as best I can with what I have. can anyone help me figure out if this will be adequate? Looking at the geometry on my mini excavators dipper arm there even less of an advantage on boom and dipper cylinder then I have here. I appreciate any help that can be provided.