Octagon dimensions Help

Discussion in 'Landscape Architecture and Design' started by McNeal Lawn, Aug 31, 2003.

  1. McNeal Lawn

    McNeal Lawn LawnSite Member
    Posts: 61

    I have a customer that wants an octagon bed installed, the bed will have a diameter of 15 feet, constructed with landscape timbers. The problem is I can not calculate the required length of the timbers nor the degree angle for the mitre cut. I am handicapped with limited math knowledge. Can anyone give me a hand in figuring out this problem? Thanks.
     
  2. capital

    capital LawnSite Member
    Posts: 118

    Suggest you use the KISS method and will find it goes easier. buy your timbers (8') length, lay them out at job site and then use a chain saw to form up the bed. you should end up around 15.5 ' across. We are currently doing a octogon patio with a circle pattern inside and went to the kiss method after playing with the math numbers. So just paint on the ground your corners and keep adjusting using a string line til u line the corners up . Then lay your timbers and begin cutting your angles at the site. remasure your angles and timber spots after each cut and u should line up correctly.
     
  3. mottster

    mottster LawnSite Member
    Posts: 191

    if you use the full 8 foot length tembers you'll end up with a 16 foot bed.
    To get the 15 foot diameter (i'm guessing you're meaning side to side and not corner to corner?) you'll need 7.5 foot lengths. cut the timbers to the proper length and then cut the angles from there. Oh...each angle will need to be 22.5 degrees.
     
  4. mdvaden

    mdvaden LawnSite Bronze Member
    Posts: 1,945

    Drawing it to scale on 8a.5 x 11 graph paper may help as a visual building block.

    We have a small miter saw, so I finish the last part of the cut with a sharp handsaw.
     
  5. McNeal Lawn

    McNeal Lawn LawnSite Member
    Posts: 61

    Thanks for the help, all of your suggestions will be used, thanks again
     
  6. AGLA

    AGLA LawnSite Bronze Member
    Posts: 1,749

    The lengths of each side should be about 5'9" and the parallel sides should be about 13'10" apart.
     
  7. jonw9

    jonw9 LawnSite Member
    Posts: 25

    Well, first is it 15' inscribed or circumscribed? Meaning 15' from point to point, or from flat to flat? That will determine length.

    AGLA is right on the inscribed bed,
    and for circumscribed sides would be 13'10" with the distance between sides being 15'
     
  8. Team Gopher

    Team Gopher LawnSite Platinum Member
    from -
    Posts: 4,041

    Here is a math site that explores the octagon.

    [​IMG]
     
  9. diginahole

    diginahole LawnSite Member
    Posts: 249

    Check your math jonw9, you should get this.

    Inscribed: 8 sides @ 5' 9". Distance between parallel sides 13' 10 ". Corner to opposite corner 15' 0".

    Circumscribed: 8 sides @ 6' 3" ( actually 6' 2 9/16"). Distance between parallel sides 15' 0". Corner to opposite corner 16' 2 13/16".
     
  10. AGLA

    AGLA LawnSite Bronze Member
    Posts: 1,749

    I think that the miter cut will be about 67 degrees.
     

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