i think i know the answer, lets see if anyone else does. if a 50 lb bag of fertilizer , rated to treat 12,500 sq ft of turf, has the numbers 20-10-10 on it, how many lbs of nitrogen per k is being applied?
bobbygedd
50*20%=10lbs
10/12.5=.8lbsN per 1k
Interesting how lars got there. I didn't think of it that way.
I believe both are right though?
10/12.5=.8lbsN per 1k
Interesting how lars got there. I didn't think of it that way.
I believe both are right though?
ok jeff, it's like this: the first number of the three is the nitrogen content in the entire bag. now, we know that 20% of the bags content is nitrogen. the application rate of this particular product is 4 lbs per thousand sq. ft, we know that cus 50 lbs treats 12,500 sq ft. so, 20% of the 4lbs, is how we determine how much nitro is going down, per 1000 sq. ft. got it?who needs ric anyhow
OK Genius
How many Pounds of actual P are you applying to the same area at the .8 lb of N rate.
Please no one answer this question but Mr Rocket Science. Oh and please no one send him the answer.
heh heh heh, yes I do know the answer.
i ussually dont make these types of comments, but here goes,
anybody not know the answer...get out of the business!
Its ok to come in here and spell badly or to use improper english (i stand guilty of both) BUT, you'd better know this stuff or learn it real quick before you leave someone an invoice for your service. Or apply for work at your local 7-11
i ussually dont make these types of comments, but here goes,
anybody not know the answer...get out of the business!
Its ok to come in here and spell badly or to use improper english (i stand guilty of both) BUT, you'd better know this stuff or learn it real quick before you leave someone an invoice for your service. Or apply for work at your local 7-11
there is a simple formula to use to find any number as far as applying fert. (Rate x area in 1000's / % = lbs to use)
For this we need to find rate.
Basic algerbra here what you do to one side you do to the other. the object is to get the rate by itself. so we start by x the % to both side so 50 x .2 =10. then you need to divide both by area so 10 / 12.5 = .8 so the answer is rate = .8
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For this we need to find rate.
Basic algerbra here what you do to one side you do to the other. the object is to get the rate by itself. so we start by x the % to both side so 50 x .2 =10. then you need to divide both by area so 10 / 12.5 = .8 so the answer is rate = .8
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