# AI in product?

Discussion in 'Pesticide & Herbicide Application' started by cycloneturf, Jul 26, 2008.

1. ### cycloneturfLawnSite Memberfrom midwestMessages: 6

How do you figure the total AI in pounds on a fifty pound bag?
Example: 24-5-11 with Mach 2 1.33%

**** 1.33 % / 50lbs = .026 lbs ?????? ***** This does not sound right

Thanx for the help!

2. ### ICT BillLawnSite Platinum Memberfrom Howard County MDMessages: 4,115

If the number was 1% and you had 50 of anything it would be 0.50, yours would be somewhere around 0.65

3. ### eagle1243LawnSite Memberfrom Rochester, NYMessages: 3

Multiply the % AI times total weight of product. Then divide by 100.

1.33 % x 50 lbs = 66.5 lbs / 100 = .665 lbs

5. ### RigglePLCLawnSite Fanaticfrom Grand Rapids MIMessages: 13,293

Buy two bags. You have a hundred pounds. 1.33 percent then equals 1.33 pounds.

6. ### cycloneturfLawnSite Memberfrom midwestMessages: 6

So with that said... a 19-0-6 Dimension .1 % would have .05 lbs of AI per 50 lb bag of fertilizer.

7. ### RunnerLawnSite Fanaticfrom Flint, MichiganMessages: 13,497

That is correct. Seems strange, doesn't it? That is like Crosscheck (bifenthrin)...It is like 3 lbs. that does an acre, I believe.