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#### McNeal Lawn

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I have a customer that wants an octagon bed installed, the bed will have a diameter of 15 feet, constructed with landscape timbers. The problem is I can not calculate the required length of the timbers nor the degree angle for the mitre cut. I am handicapped with limited math knowledge. Can anyone give me a hand in figuring out this problem? Thanks.

#### capital

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Suggest you use the KISS method and will find it goes easier. buy your timbers (8') length, lay them out at job site and then use a chain saw to form up the bed. you should end up around 15.5 ' across. We are currently doing a octogon patio with a circle pattern inside and went to the kiss method after playing with the math numbers. So just paint on the ground your corners and keep adjusting using a string line til u line the corners up . Then lay your timbers and begin cutting your angles at the site. remasure your angles and timber spots after each cut and u should line up correctly.

#### mottster

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if you use the full 8 foot length tembers you'll end up with a 16 foot bed.
To get the 15 foot diameter (i'm guessing you're meaning side to side and not corner to corner?) you'll need 7.5 foot lengths. cut the timbers to the proper length and then cut the angles from there. Oh...each angle will need to be 22.5 degrees.

#### McNeal Lawn

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Thanks for the help, all of your suggestions will be used, thanks again

#### AGLA

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The lengths of each side should be about 5'9" and the parallel sides should be about 13'10" apart.

#### jonw9

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Well, first is it 15' inscribed or circumscribed? Meaning 15' from point to point, or from flat to flat? That will determine length.

AGLA is right on the inscribed bed,
and for circumscribed sides would be 13'10" with the distance between sides being 15'

#### Team Gopher

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Here is a math site that explores the octagon.

#### diginahole

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Check your math jonw9, you should get this.

Inscribed: 8 sides @ 5' 9". Distance between parallel sides 13' 10 ". Corner to opposite corner 15' 0".

Circumscribed: 8 sides @ 6' 3" ( actually 6' 2 9/16"). Distance between parallel sides 15' 0". Corner to opposite corner 16' 2 13/16".

#### AGLA

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I think that the miter cut will be about 67 degrees.

#### diginahole

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You think right AGLA however, when cutting mitres you would measue the angles as 22.5 degrees left or right of 90. That is how a mitre box would be marked. Now in the case of building a timber octagon I would likely cut the ends at 45 and make overlapping joints rather than a mitred joint. Much stronger.

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